Cook Lewis
03/12/2023 · Junior High School

\( M = - \frac { 4 } { 3 } j ( 6 , - 4 ) \)

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The expression you've provided seems to represent a complex number or a vector in the context of a mathematical operation. Let's break it down: 1. The term \( -\frac{4}{3} j \) suggests a multiplication by a complex unit \( j \), which is often used to denote the imaginary unit in electrical engineering and mathematics, where \( j^2 = -1 \). 2. The coordinates \( (6, -4) \) could represent a point in the Cartesian plane or a vector. To compute \( M \), we can multiply the scalar \( -\frac{4}{3} j \) by the vector \( (6, -4) \). This operation typically involves multiplying each component of the vector by the scalar. Let's perform the multiplication: \[ M = -\frac{4}{3} j (6, -4) = \left(-\frac{4}{3} j \cdot 6, -\frac{4}{3} j \cdot -4\right) \] Calculating each component: 1. For the first component: \[ -\frac{4}{3} j \cdot 6 = -8 j \] 2. For the second component: \[ -\frac{4}{3} j \cdot -4 = \frac{16}{3} j \] Thus, we can express \( M \) as: \[ M = (-8 j, \frac{16}{3} j) \] This means that \( M \) is a vector in the complex plane with components \( -8 j \) and \( \frac{16}{3} j \). If you need further clarification or a different interpretation, please let me know!

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\( M = (-8 j, \frac{16}{3} j) \)
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