\( ( 14 + \square ) \cdot \square = \square \cdot 3 + 8 \cdot \square \)

To solve the equation \( (14 + \square) \cdot \square = \square \cdot 3 + 8 \cdot \square \), we can start by letting \( x = \square \). This gives us the equation: \[ (14 + x) \cdot x = x \cdot 3 + 8 \cdot x \] Now, we can simplify both sides of the equation. The left side becomes: \[ (14 + x) \cdot x = 14x + x^2 \] The right side simplifies to: \[ x \cdot 3 + 8 \cdot x = 3x + 8x = 11x \] Now we can rewrite the equation as: \[ 14x + x^2 = 11x \] Next, we can move all terms to one side of the equation: \[ x^2 + 14x - 11x = 0 \] This simplifies to: \[ x^2 + 3x = 0 \] Now, we can factor the left side: \[ x(x + 3) = 0 \] Setting each factor equal to zero gives us the solutions: 1. \( x = 0 \) 2. \( x + 3 = 0 \) which gives \( x = -3 \) Thus, the solutions for \( \square \) are: \[ \boxed{0} \quad \text{and} \quad \boxed{-3} \]