Note \( 1+x+=\oplus \) \( 2-x-=\oplus \) \( 3+x-=\square \)

It seems like you're using some unconventional notation with the symbols \( \oplus \) and \( \square \). Let's break down the expressions you've provided: 1. \( 1 + x = \oplus \) 2. \( 2 - x = \oplus \) 3. \( 3 + x - = \square \) To interpret these, we need to clarify what \( \oplus \) and \( \square \) represent. If we assume \( \oplus \) and \( \square \) are placeholders for some values or operations, we can analyze the equations accordingly. From the first two equations, we can set them equal to each other since they both equal \( \oplus \): \[ 1 + x = 2 - x \] Now, let's solve for \( x \): \[ 1 + x + x = 2 \] \[ 2x = 1 \] \[ x = \frac{1}{2} \] Now that we have \( x \), we can substitute it back into either equation to find \( \oplus \): Using the first equation: \[ 1 + \frac{1}{2} = \oplus \] \[ \oplus = \frac{3}{2} \] Now, we can substitute \( x \) into the third equation to find \( \square \): \[ 3 + \frac{1}{2} - = \square \] However, the expression \( 3 + x - \) is unclear. If we assume it means \( 3 + x \) (without any operation after), we can calculate: \[ 3 + \frac{1}{2} = \square \] \[ \square = \frac{7}{2} \] So, summarizing the results: - \( x = \frac{1}{2} \) - \( \oplus = \frac{3}{2} \) - \( \square = \frac{7}{2} \) If you meant something different with the notation, please clarify!