A chef prepared five chocolate tortes for a dinner party. The guests consumed \( 25 / 16 \) tortes. How many tortes are left?

To find out how many chocolate tortes are left after the guests consumed \( \frac{25}{16} \) tortes, we start with the total number of tortes prepared by the chef, which is 5. First, we need to express 5 in terms of sixteenths to make the subtraction easier: \[ 5 = \frac{5 \times 16}{16} = \frac{80}{16} \] Now we can subtract the amount consumed from the total amount prepared: \[ \text{Tortes left} = \text{Total tortes} - \text{Tortes consumed} = \frac{80}{16} - \frac{25}{16} \] Since both fractions have the same denominator, we can subtract the numerators directly: \[ \text{Tortes left} = \frac{80 - 25}{16} = \frac{55}{16} \] Thus, the number of tortes left is: \[ \frac{55}{16} \] To express this as a mixed number, we divide 55 by 16: \[ 55 \div 16 = 3 \quad \text{(with a remainder of 7)} \] This means: \[ \frac{55}{16} = 3 \frac{7}{16} \] Therefore, the final answer is that there are \( \frac{55}{16} \) tortes left, or equivalently, \( 3 \frac{7}{16} \) tortes left.