Which is one way to check \( 102 \div 6=17 ? \) A) \( 105 \div 5=21 \) B) \( 100 \div 5=20 \) C) \( 105 \div 10=10.5 \) D) \( 102 \div 10=10.2 \)

To check if \( 102 \div 6 = 17 \), you can use a method that involves rounding or simplifying the numbers to make the division easier to verify. Let's look at the options provided: A) \( 105 \div 5 = 21 \) B) \( 100 \div 5 = 20 \) C) \( 105 \div 10 = 10.5 \) D) \( 102 \div 10 = 10.2 \) The correct answer is: B) \( 100 \div 5 = 20 \) Here's why: - \( 102 \div 6 \) is close to \( 100 \div 6 \), which is approximately \( 16.67 \). Since \( 100 \div 6 \) is a bit less than \( 17 \), and \( 102 \) is two more than \( 100 \), the result will be a bit more than \( 17 \). - \( 100 \div 5 \) is exactly \( 20 \), which is a bit more than \( 17 \). This is a reasonable approximation to check if \( 102 \div 6 \) is close to \( 17 \). The other options are not as close to \( 17 \) as \( 100 \div 5 \): - \( 105 \div 5 = 21 \) is too high. - \( 105 \div 10 = 10.5 \) is too low. - \( 102 \div 10 = 10.2 \) is too low. So, the best way to check \( 102 \div 6 = 17 \) from the given options is to use \( 100 \div 5 = 20 \).