Bradley Vargas
04/21/2024 · Primary School
11) Discussion Topic: 1. A mass-spring system has a mass ( m ) of 0.5 kg and a stiffness \( (\mathrm{k}) \) of \( 100 \mathrm{~N} / \mathrm{m} \). Calculate the natural frequency ( \( \omega \mathrm{n}) \) of the system.
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Step-by-step Solution
The natural frequency \( \omega_n \) of a mass-spring system can be calculated using the formula:
\[
\omega_n = \sqrt{\frac{k}{m}}
\]
where:
- \( k \) is the stiffness of the spring (in N/m),
- \( m \) is the mass (in kg).
Given:
- \( m = 0.5 \, \text{kg} \)
- \( k = 100 \, \text{N/m} \)
Now, substituting the values into the formula:
\[
\omega_n = \sqrt{\frac{100 \, \text{N/m}}{0.5 \, \text{kg}}}
\]
Calculating the fraction:
\[
\frac{100}{0.5} = 200
\]
Now, taking the square root:
\[
\omega_n = \sqrt{200} \approx 14.14 \, \text{rad/s}
\]
Thus, the natural frequency of the system is approximately \( 14.14 \, \text{rad/s} \).
Quick Answer
The natural frequency \( \omega_n \) is approximately \( 14.14 \, \text{rad/s} \).
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