Wood Phillips
07/26/2023 · High School

ide what number must be added to both sides of the equation to make the left side a perfect square trinomial, then fact \( y^{2}-8 y=5 \) d a number to both sides of the equation to make the left side a perfect square trinomial. \( \begin{array}{l}-8 y+\square=5+\square \\ \text { ype integers or simplified fractions.) }\end{array} \)

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To make the left side of the equation \( y^2 - 8y = 5 \) a perfect square trinomial, we need to complete the square. 1. Start with the equation: \[ y^2 - 8y = 5 \] 2. To complete the square, take the coefficient of \( y \) (which is \(-8\)), divide it by 2, and then square it: \[ \left(-\frac{8}{2}\right)^2 = (-4)^2 = 16 \] 3. Add this number (16) to both sides of the equation: \[ y^2 - 8y + 16 = 5 + 16 \] 4. This simplifies to: \[ y^2 - 8y + 16 = 21 \] 5. Now, the left side is a perfect square trinomial, which can be factored as: \[ (y - 4)^2 = 21 \] So, the number that must be added to both sides of the equation is \( 16 \). In summary, the completed equation is: \[ y^2 - 8y + 16 = 5 + 16 \] or \[ y^2 - 8y + \square = 5 + \square \] where \( \square = 16 \).

Quick Answer

The number to add to both sides is \( 16 \). The completed equation is: \[ y^2 - 8y + 16 = 5 + 16 \]
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