Joseph Chen
06/11/2023 · High School

[0/11.11 Points] DETAILS A car wash firm calculates that its daily profit (in dollars) depends on the number \( n \) of workers it employs according to the formula \[ P=-600 n+25 n^{2}-0.005 n^{4} \text {. } \] Calculate the marginal product at an employment level of 50 workers. HINT [See Example 3.] \( \$ \$ \)

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To calculate the marginal product at an employment level of 50 workers, we need to find the derivative of the profit function with respect to the number of workers \( n \) and then evaluate it at \( n = 50 \). Given the profit function: \[ P = -600n + 25n^2 - 0.005n^4 \] The marginal product is the derivative of the profit function with respect to the number of workers \( n \). Let's find the derivative of the profit function. Evaluate the derivative by following steps: - step0: Evaluate the derivative: \(\frac{d}{dn}\left(-600n+25n^{2}-0.005n^{4}\right)\) - step1: Use differentiation rules: \(-\frac{d}{dn}\left(600n\right)+\frac{d}{dn}\left(25n^{2}\right)-\frac{d}{dn}\left(0.005n^{4}\right)\) - step2: Calculate: \(-600+50n-0.02n^{3}\) The derivative of the profit function with respect to the number of workers \( n \) is: \[ \frac{dP}{dn} = -600 + 50n - 0.02n^3 \] Now, we need to evaluate this derivative at \( n = 50 \) to find the marginal product at an employment level of 50 workers. Let's substitute \( n = 50 \) into the derivative expression and calculate the result. Evaluate the expression by following steps: - step0: Evaluate: \(-600+50n-0.02n^{3}\) - step1: Substitute: \(-600+50\times 50-0.02\times 50^{3}\) - step2: Multiply the numbers: \(-600+2500-0.02\times 50^{3}\) - step3: Multiply the numbers: \(-600+2500-2500\) - step4: Calculate: \(-600\) The marginal product at an employment level of 50 workers is $-600. Therefore, the marginal product at an employment level of 50 workers is $-600.

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The marginal product at 50 workers is $-600.
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