Yout project requires a boand that has a length of \( 5 \frac{3}{16} \) inches. You found a board that has a length of \( 9 \frac{1}{-} \) inches. How much of the board needs to by ut off to use it for your project?

To determine how much of the board needs to be cut off, we first need to convert the mixed numbers into improper fractions. 1. Convert \( 5 \frac{3}{16} \) inches to an improper fraction: \[ 5 \frac{3}{16} = \frac{5 \times 16 + 3}{16} = \frac{80 + 3}{16} = \frac{83}{16} \] 2. Convert \( 9 \frac{1}{-} \) inches to an improper fraction. However, it seems there is a typo in the length of the board. Assuming you meant \( 9 \frac{1}{16} \): \[ 9 \frac{1}{16} = \frac{9 \times 16 + 1}{16} = \frac{144 + 1}{16} = \frac{145}{16} \] Now, we need to find out how much needs to be cut off from the board: \[ \text{Length to cut off} = \text{Length of the board} - \text{Length required} \] \[ = \frac{145}{16} - \frac{83}{16} \] \[ = \frac{145 - 83}{16} = \frac{62}{16} \] Now, simplify \( \frac{62}{16} \): \[ \frac{62 \div 2}{16 \div 2} = \frac{31}{8} \] Convert \( \frac{31}{8} \) back to a mixed number: \[ 31 \div 8 = 3 \quad \text{remainder } 7 \] So, \( \frac{31}{8} = 3 \frac{7}{8} \). Thus, you need to cut off \( 3 \frac{7}{8} \) inches from the board to use it for your project.