Long Beck
09/15/2023 · Junior High School
24- Maximum number of 60 - W light bulbs you can connect in parallel in \( 120-\mathrm{v} \) home circuit without tripping 30 A circuit breaker? (a) 11 bulbs (b) 28 bulbs (c) 36 bulbs (d) 60 bulbs
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Tutor-Verified Answer
Step-by-step Solution
To determine the maximum number of 60 W light bulbs that can be connected in parallel without tripping a 30 A circuit breaker, we can follow these steps:
1. **Calculate the total power that the circuit can handle:**
The circuit is rated for 30 A at 120 V. The total power (P) can be calculated using the formula:
\[
P = V \times I
\]
where \( V \) is the voltage (120 V) and \( I \) is the current (30 A).
\[
P = 120 \, \text{V} \times 30 \, \text{A} = 3600 \, \text{W}
\]
2. **Calculate the power consumed by one light bulb:**
Each light bulb consumes 60 W.
3. **Determine the maximum number of bulbs:**
To find the maximum number of bulbs (N) that can be connected without exceeding the total power limit, we can use the formula:
\[
N = \frac{\text{Total Power}}{\text{Power per Bulb}} = \frac{3600 \, \text{W}}{60 \, \text{W}} = 60
\]
Thus, the maximum number of 60 W light bulbs that can be connected in parallel without tripping the 30 A circuit breaker is **60 bulbs**.
The correct answer is:
(d) 60 bulbs.
Quick Answer
The maximum number of 60 W bulbs that can be connected without tripping the circuit breaker is 60 bulbs.
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