Reese Griffin
10/21/2023 · High School
The functions \( f \) and \( g \) are defined as \( f(x)=4 x-3 \) and \( g(x)=-9 x^{2} \). a) Find the domain of \( f, g, f+g, f-g, f g, f f, \frac{f}{g} \), and \( \frac{g}{f} \). b) Find \( (f+g)(x),(f-g)(x),(f g)(x),(f f)(x),\left(\frac{f}{g}\right)(x) \), and \( \left(\frac{g}{f}\right)(x) \). a) The domain of \( f \) is \( (-\infty, \infty) \). (Type your answer in interval notation.) The domain of \( g \) is \( (-\infty, \infty) \). (Type your answer in interval notation.) The domain of \( f+g \) is (Type your answer in interval notation.)
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Step-by-step Solution
To find the domains of the functions \( f \) and \( g \), as well as their combinations, we will analyze each function and operation step by step.
### a) Finding the domains
1. **Domain of \( f(x) = 4x - 3 \)**:
- This is a linear function, which is defined for all real numbers.
- **Domain of \( f \)**: \( (-\infty, \infty) \)
2. **Domain of \( g(x) = -9x^2 \)**:
- This is a quadratic function, which is also defined for all real numbers.
- **Domain of \( g \)**: \( (-\infty, \infty) \)
3. **Domain of \( f + g \)**:
- Since both \( f \) and \( g \) are defined for all real numbers, their sum is also defined for all real numbers.
- **Domain of \( f + g \)**: \( (-\infty, \infty) \)
4. **Domain of \( f - g \)**:
- Similar to the sum, the difference of two functions defined for all real numbers is also defined for all real numbers.
- **Domain of \( f - g \)**: \( (-\infty, \infty) \)
5. **Domain of \( fg \)**:
- The product of two functions defined for all real numbers is also defined for all real numbers.
- **Domain of \( fg \)**: \( (-\infty, \infty) \)
6. **Domain of \( ff \)**:
- This is simply \( f(f(x)) \), which is defined for all real numbers since \( f \) is defined for all real numbers.
- **Domain of \( ff \)**: \( (-\infty, \infty) \)
7. **Domain of \( \frac{f}{g} \)**:
- The quotient is defined wherever \( g(x) \neq 0 \). We need to find where \( g(x) = -9x^2 = 0 \).
- This occurs at \( x = 0 \). Therefore, the domain excludes \( x = 0 \).
- **Domain of \( \frac{f}{g} \)**: \( (-\infty, 0) \cup (0, \infty) \)
8. **Domain of \( \frac{g}{f} \)**:
- The quotient is defined wherever \( f(x) \neq 0 \). We need to find where \( f(x) = 4x - 3 = 0 \).
- This occurs at \( x = \frac{3}{4} \). Therefore, the domain excludes \( x = \frac{3}{4} \).
- **Domain of \( \frac{g}{f} \)**: \( (-\infty, \frac{3}{4}) \cup (\frac{3}{4}, \infty) \)
### Summary of Domains
- Domain of \( f \): \( (-\infty, \infty) \)
- Domain of \( g \): \( (-\infty, \infty) \)
- Domain of \( f + g \): \( (-\infty, \infty) \)
- Domain of \( f - g \): \( (-\infty, \infty) \)
- Domain of \( fg \): \( (-\infty, \infty) \)
- Domain of \( ff \): \( (-\infty, \infty) \)
- Domain of \( \frac{f}{g} \): \( (-\infty, 0) \cup (0, \infty) \)
- Domain of \( \frac{g}{f} \): \( (-\infty, \frac{3}{4}) \cup (\frac{3}{4}, \infty) \)
### b) Finding the functions
1. **Finding \( (f + g)(x) \)**:
\[
(f + g)(x) = f(x) + g(x) = (4x - 3) + (-9x^2) = -9x^2 + 4x - 3
\]
2. **Finding \( (f - g)(x) \)**:
\[
(f - g)(x) = f(x) - g(x) = (4x - 3) - (-9x^2) = 9x^2 + 4x - 3
\]
3. **Finding \( (fg)(x) \)**:
\[
(fg)(x) =
Quick Answer
- Domain of \( f \): \( (-\infty, \infty) \)
- Domain of \( g \): \( (-\infty, \infty) \)
- Domain of \( f + g \): \( (-\infty, \infty) \)
- Domain of \( f - g \): \( (-\infty, \infty) \)
- Domain of \( fg \): \( (-\infty, \infty) \)
- Domain of \( ff \): \( (-\infty, \infty) \)
- Domain of \( \frac{f}{g} \): \( (-\infty, 0) \cup (0, \infty) \)
- Domain of \( \frac{g}{f} \): \( (-\infty, \frac{3}{4}) \cup (\frac{3}{4}, \infty) \)
- \( (f + g)(x) \): \( -9x^2 + 4x - 3 \)
- \( (f - g)(x) \): \( 9x^2 + 4x - 3 \)
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