d) $$ 56^{\circ}-38^{\circ} 42^{\prime} $$

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$$ 17^{\circ} 18^{\prime} $$ To perform the subtraction $$ 56^{\circ} - 38^{\circ} 42^{\prime} $$, we first need to express both angles in a consistent format. 1. Convert $$ 56^{\circ} $$ into degrees and minutes: $$ 56^{\circ} = 56^{\circ} 0^{\prime} $$ 2. Now, we can perform the subtraction: $$ 56^{\circ} 0^{\prime} - 38^{\circ} 42^{\prime} $$ 3. Subtract the degrees: $$ 56^{\circ} - 38^{\circ} = 18^{\circ} $$ 4. Now, we need to subtract the minutes. Since we have $$ 0^{\prime} $$ minutes in the first angle, we need to borrow 1 degree (which is equivalent to 60 minutes) from $$ 18^{\circ} $$: $$ 18^{\circ} 0^{\prime} = 17^{\circ} 60^{\prime} $$ 5. Now we can perform the subtraction of the minutes: $$ 17^{\circ} 60^{\prime} - 38^{\circ} 42^{\prime} = 17^{\circ} 60^{\prime} - 0^{\circ} 38^{\prime} - 38^{\circ} 42^{\prime} $$ $$ = (60^{\prime} - 42^{\prime}) = 18^{\prime} $$ 6. Now combine the results: $$ 17^{\circ} - 38^{\circ} = -21^{\circ} + 18^{\prime} $$ Thus, the final result of the subtraction $$ 56^{\circ} - 38^{\circ} 42^{\prime} $$ is: $$ 17^{\circ} 18^{\prime} $$ So, the answer is: $$ 17^{\circ} 18^{\prime} $$

d) \( 56^{\circ}-38^{\circ} 42^{\prime} \)

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d) \( 56^{\circ}-38^{\circ} 42^{\prime} \)

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