Write the point-slope form of the line that passes through \( (6,1) \) and is parallel to a line with a slope of -3 . Include all of your work In your final answer. Type your answer in the box provided to submit your solution.

To find the point-slope form of the line that passes through the point \( (6,1) \) and is parallel to a line with a slope of -3, we can use the point-slope form of a linear equation: \[ y - y_1 = m(x - x_1) \] where: - \( (x_1, y_1) \) is the point through which the line passes, in this case, \( (6,1) \). - \( m \) is the slope of the line, which is -3 for the line we are parallel to. Substitute the values into the point-slope form: \[ y - 1 = -3(x - 6) \] Now, simplify the equation: \[ y - 1 = -3x + 18 \] \[ y = -3x + 19 \] Therefore, the point-slope form of the line that passes through \( (6,1) \) and is parallel to a line with a slope of -3 is \( y = -3x + 19 \).