Logan Bolton
09/09/2024 · Middle School
\( \operatorname { Lim } _ { t \rightarrow \infty } 2 \int _ { 0 } ^ { t } \frac { 1 } { n ( n + 1 ) } \)
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Step-by-step Solution
Para resolver el límite \( \operatorname{Lim}_{t \rightarrow \infty} 2 \int_{0}^{t} \frac{1}{n(n+1)} \, dn \), primero necesitamos calcular la integral \( \int \frac{1}{n(n+1)} \, dn \).
Podemos descomponer la fracción usando fracciones parciales:
\[
\frac{1}{n(n+1)} = \frac{A}{n} + \frac{B}{n+1}
\]
Multiplicando ambos lados por \( n(n+1) \) y resolviendo para \( A \) y \( B \):
\[
1 = A(n+1) + Bn
\]
Si tomamos \( n = 0 \):
\[
1 = A(0 + 1) \implies A = 1
\]
Si tomamos \( n = -1 \):
\[
1 = B(-1) \implies B = -1
\]
Por lo tanto, podemos escribir:
\[
\frac{1}{n(n+1)} = \frac{1}{n} - \frac{1}{n+1}
\]
Ahora, integramos:
\[
\int \frac{1}{n(n+1)} \, dn = \int \left( \frac{1}{n} - \frac{1}{n+1} \right) \, dn = \ln |n| - \ln |n+1| + C = \ln \left| \frac{n}{n+1} \right| + C
\]
Ahora evaluamos la integral definida:
\[
\int_{0}^{t} \frac{1}{n(n+1)} \, dn = \left[ \ln \left| \frac{n}{n+1} \right| \right]_{0}^{t}
\]
Evaluamos en los límites:
1. Para \( n = t \):
\[
\ln \left| \frac{t}{t+1} \right|
\]
2. Para \( n = 0 \):
\[
\lim_{n \to 0} \ln \left| \frac{n}{n+1} \right| = \ln(0) \text{ (indeterminado, pero se puede analizar el límite)}
\]
Sin embargo, al evaluar el límite cuando \( n \) se aproxima a 0, notamos que:
\[
\frac{n}{n+1} \to 0 \implies \ln \left| \frac{n}{n+1} \right| \to -\infty
\]
Por lo tanto, la integral se comporta de la siguiente manera:
\[
\int_{0}^{t} \frac{1}{n(n+1)} \, dn = \ln \left| \frac{t}{t+1} \right| - \lim_{n \to 0} \ln \left| \frac{n}{n+1} \right| \to \ln \left| \frac{t}{t+1} \right| + \infty
\]
Esto implica que la integral diverge a \( \infty \) cuando \( t \to \infty \).
Finalmente, evaluamos el límite:
\[
\operatorname{Lim}_{t \rightarrow \infty} 2 \int_{0}^{t} \frac{1}{n(n+1)} \, dn = \operatorname{Lim}_{t \rightarrow \infty} 2 \left( \ln \left| \frac{t}{t+1} \right| + \infty \right) = \infty
\]
Por lo tanto, el resultado es:
\[
\boxed{\infty}
\]
Quick Answer
El límite es \( \infty \).
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