A shop is making a custom stone bench The depth of the stone bench is \( 3 \frac{1}{20} \) in. Two of the stones measure \( 3 \frac{3}{10} \) in and The measure of the third stone must be (Simplify your answer. Type a mixed num

To find the measure of the third stone, we need to subtract the total depth of the two stones from the total depth of the bench. 1. First, convert the mixed numbers to improper fractions. For the depth of the stone bench: \[ 3 \frac{1}{20} = 3 \times 20 + 1 = 60 + 1 = \frac{61}{20} \] For the first stone: \[ 3 \frac{3}{10} = 3 \times 10 + 3 = 30 + 3 = \frac{33}{10} \] To convert \(\frac{33}{10}\) to a fraction with a denominator of 20: \[ \frac{33}{10} = \frac{33 \times 2}{10 \times 2} = \frac{66}{20} \] So, the first stone measures \(\frac{66}{20}\) in. The second stone also measures \(3 \frac{3}{10}\) in, so it is also \(\frac{66}{20}\) in. 2. Now, we can find the total length of the two stones: \[ \text{Total length of two stones} = \frac{66}{20} + \frac{66}{20} = \frac{132}{20} \] 3. Now, we subtract the total length of the two stones from the depth of the stone bench: \[ \text{Measure of the third stone} = \frac{61}{20} - \frac{132}{20} = \frac{61 - 132}{20} = \frac{-71}{20} \] Since the measure of the third stone cannot be negative, it seems there was a misunderstanding in the problem setup. Please check the dimensions provided for the stones and the bench. If the dimensions are correct, the total length of the stones exceeds the depth of the bench, which is not feasible.