Long Adkins
02/13/2023 · Junior High School

Write a quadratic equation in the form \( x^{2}+b x+c=0 \) that has the following r \[ \text { Roots: }-4 \pm \sqrt{10} \] Answer

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To find a quadratic equation with the given roots \( -4 \pm \sqrt{10} \), we can use the fact that if \( r_1 \) and \( r_2 \) are the roots of the quadratic equation, then the equation can be expressed in the form: \[ x^2 - (r_1 + r_2)x + (r_1 \cdot r_2) = 0 \] First, we identify the roots: - \( r_1 = -4 + \sqrt{10} \) - \( r_2 = -4 - \sqrt{10} \) Next, we calculate the sum of the roots \( r_1 + r_2 \): \[ r_1 + r_2 = (-4 + \sqrt{10}) + (-4 - \sqrt{10}) = -8 \] Now, we calculate the product of the roots \( r_1 \cdot r_2 \): \[ r_1 \cdot r_2 = (-4 + \sqrt{10})(-4 - \sqrt{10}) = (-4)^2 - (\sqrt{10})^2 = 16 - 10 = 6 \] Now we can substitute these values into the quadratic equation form: \[ x^2 - (r_1 + r_2)x + (r_1 \cdot r_2) = 0 \] Substituting the values we found: \[ x^2 - (-8)x + 6 = 0 \] This simplifies to: \[ x^2 + 8x + 6 = 0 \] Thus, the quadratic equation in the form \( x^2 + bx + c = 0 \) is: \[ \boxed{x^2 + 8x + 6 = 0} \]

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The quadratic equation is \( x^2 + 8x + 6 = 0 \).
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