Tucker Zimmerman
02/16/2023 · Primary School
e) \( \left(\frac{-9}{3}\right)(-7) \) g) \( \left(\frac{24}{9}\right)\left(\frac{-56}{48}\right)= \) \( 1\left(\frac{-21}{-7}\right)\left(\frac{-9}{3}\right) \)
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
Let's solve each expression step by step.
**e)**
\[
\left(\frac{-9}{3}\right)(-7)
\]
First, simplify \(\frac{-9}{3}\):
\[
\frac{-9}{3} = -3
\]
Now, multiply by \(-7\):
\[
(-3)(-7) = 21
\]
So, the result for e) is:
\[
\boxed{21}
\]
---
**g)**
\[
\left(\frac{24}{9}\right)\left(\frac{-56}{48}\right)
\]
First, simplify each fraction:
\[
\frac{24}{9} = \frac{8}{3} \quad \text{(dividing numerator and denominator by 3)}
\]
\[
\frac{-56}{48} = \frac{-7}{6} \quad \text{(dividing numerator and denominator by 8)}
\]
Now, multiply the simplified fractions:
\[
\left(\frac{8}{3}\right)\left(\frac{-7}{6}\right) = \frac{8 \cdot -7}{3 \cdot 6} = \frac{-56}{18}
\]
Now simplify \(\frac{-56}{18}\):
\[
\frac{-56}{18} = \frac{-28}{9} \quad \text{(dividing numerator and denominator by 2)}
\]
So, the result for g) is:
\[
\boxed{\frac{-28}{9}}
\]
---
Now, let's evaluate the expression:
\[
1\left(\frac{-21}{-7}\right)\left(\frac{-9}{3}\right)
\]
First, simplify \(\frac{-21}{-7}\):
\[
\frac{-21}{-7} = 3
\]
Next, simplify \(\frac{-9}{3}\):
\[
\frac{-9}{3} = -3
\]
Now, multiply:
\[
1 \cdot 3 \cdot (-3) = 3 \cdot (-3) = -9
\]
So, the result for this expression is:
\[
\boxed{-9}
\]
Quick Answer
e) \( 21 \)
g) \( \frac{-28}{9} \)
-9
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