Mills Simmons
03/01/2024 · Elementary School
Assume that when human resource managers are randomly selected, \( 62 \% \) say job applicants should follow up within two weeks. If 5 human resource managers are randomly selected, find the probability that exactly 3 of them say job applicants should follow up within two weeks. The probability is (Round to four decimal places as needed.)
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To find the probability that exactly 3 out of 5 human resource managers say job applicants should follow up within two weeks, we can use the binomial probability formula.
Given:
- Probability of a human resource manager saying job applicants should follow up within two weeks: \( p = 0.62 \)
- Number of human resource managers selected: \( n = 5 \)
- Number of human resource managers saying job applicants should follow up within two weeks: \( k = 3 \)
The binomial probability formula is:
\[ P(X = k) = \binom{n}{k} \times p^k \times (1-p)^{n-k} \]
Substitute the given values into the formula:
\[ P(X = 3) = \binom{5}{3} \times 0.62^3 \times (1-0.62)^{5-3} \]
Now, we can calculate the probability using the binomial probability formula.
Calculate the value by following steps:
- step0: Calculate:
\( { }_{5}C_{3}\times 0.62^{3}\left(1-0.62\right)^{5-3}\)
- step1: Subtract the numbers:
\( { }_{5}C_{3}\times 0.62^{3}\times 0.38^{5-3}\)
- step2: Subtract the numbers:
\( { }_{5}C_{3}\times 0.62^{3}\times 0.38^{2}\)
- step3: Expand the expression:
\(\frac{5!}{3!\times \left(5-3\right)!}\times 0.62^{3}\times 0.38^{2}\)
- step4: Subtract the numbers:
\(\frac{5!}{3!\times 2!}\times 0.62^{3}\times 0.38^{2}\)
- step5: Reduce the fraction:
\(\frac{5\times 4}{2!}\times 0.62^{3}\times 0.38^{2}\)
- step6: Multiply the numbers:
\(\frac{20}{2!}\times 0.62^{3}\times 0.38^{2}\)
- step7: Divide the terms:
\(10\times 0.62^{3}\times 0.38^{2}\)
- step8: Convert the expressions:
\(10\left(\frac{31}{50}\right)^{3}\times 0.38^{2}\)
- step9: Convert the expressions:
\(10\left(\frac{31}{50}\right)^{3}\left(\frac{19}{50}\right)^{2}\)
- step10: Simplify:
\(10\times \frac{31^{3}}{50^{3}}\times \left(\frac{19}{50}\right)^{2}\)
- step11: Multiply the terms:
\(\frac{31^{3}}{12500}\left(\frac{19}{50}\right)^{2}\)
- step12: Evaluate the power:
\(\frac{31^{3}}{12500}\times \frac{19^{2}}{50^{2}}\)
- step13: Multiply the fractions:
\(\frac{31^{3}\times 19^{2}}{12500\times 50^{2}}\)
- step14: Multiply:
\(\frac{10754551}{31250000}\)
The probability that exactly 3 out of 5 human resource managers say job applicants should follow up within two weeks is approximately 0.3441 (rounded to four decimal places).
Quick Answer
The probability is approximately 0.3441.
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