\text{Evaluate the determinant using the formula }\left| \begin{array} { l l l } { a } & { b } \\ { c } & { d } \end{array} \right| = ad - bc
4\times 2-5\left(-3\right)
Calculate the product
8-5\left(-3\right)
Calculate the product
8-\left(-15\right)
Solution
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Evaluate
8-\left(-15\right)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
\text{Since the determinant is not 0,substitute a=}4\text{,b=}5\text{,c=}-3\text{ and d=}2\text{ into the formula for the inverse, }\frac{1}{ad-bc}\left[ \begin{array} { r r r } { d } & { -b } \\ {- c } & { a } \end{array} \right]