Erickson Clark
07/23/2023 · Junior High School
Find the exact value. \( \frac{\sin 35^{\circ}}{\cos 35^{\circ}}-\tan 35^{\circ}-1= \) Fill in blank
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Tutor-Verified Answer
Step-by-step Solution
Calculate or simplify the expression \( \frac{\sin(35)}{\cos(35)}-\tan(35)-1 \).
Calculate the value by following steps:
- step0: Calculate:
\(\frac{\sin\left(35\right)}{\cos\left(35\right)}-\tan\left(35\right)-1\)
- step1: Subtract the terms:
\(\frac{\sin\left(35\right)-\tan\left(35\right)\cos\left(35\right)}{\cos\left(35\right)}-1\)
- step2: Reduce fractions to a common denominator:
\(\frac{\sin\left(35\right)-\tan\left(35\right)\cos\left(35\right)}{\cos\left(35\right)}-\frac{\cos\left(35\right)}{\cos\left(35\right)}\)
- step3: Transform the expression:
\(\frac{\sin\left(35\right)-\tan\left(35\right)\cos\left(35\right)-\cos\left(35\right)}{\cos\left(35\right)}\)
- step4: Transform the expression:
\(\frac{-\cos\left(35\right)}{\cos\left(35\right)}\)
- step5: Rewrite the expression:
\(-\frac{\cos\left(35\right)}{\cos\left(35\right)}\)
- step6: Reduce the fraction:
\(-1\)
The exact value of \( \frac{\sin 35^{\circ}}{\cos 35^{\circ}}-\tan 35^{\circ}-1 \) is -1.
Quick Answer
The exact value is -1.
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