Wagner Ellis
02/09/2024 · Middle School
1. Factorize each of the following expressions: \( \begin{array}{ll}\text { (a) } 12 x^{2}+9 x & \text { (b) } 20 x^{2}-4 x \\ \text { (c) }-20 x^{2}-15 x^{2} & \text { (d) }-6 x+4 x^{2}\end{array} \)
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
To factorize each of the given expressions, we will look for the greatest common factor (GCF) in each case.
### (a) \( 12x^2 + 9x \)
1. Identify the GCF of the coefficients (12 and 9), which is 3.
2. The variable part has \(x\) as a common factor.
3. Factor out the GCF:
\[
12x^2 + 9x = 3x(4x + 3)
\]
### (b) \( 20x^2 - 4x \)
1. Identify the GCF of the coefficients (20 and 4), which is 4.
2. The variable part has \(x\) as a common factor.
3. Factor out the GCF:
\[
20x^2 - 4x = 4x(5x - 1)
\]
### (c) \( -20x^2 - 15x^2 \)
1. Combine like terms first:
\[
-20x^2 - 15x^2 = -35x^2
\]
2. The GCF here is \(-35x^2\) (since we can factor out the negative sign).
3. Factor out the GCF:
\[
-35x^2 = -5x^2(7)
\]
### (d) \( -6x + 4x^2 \)
1. Identify the GCF of the coefficients (-6 and 4), which is 2.
2. The variable part has \(x\) as a common factor.
3. Factor out the GCF, remembering to factor out the negative:
\[
-6x + 4x^2 = 2x(2x - 3)
\]
### Summary of Factorizations:
- (a) \( 12x^2 + 9x = 3x(4x + 3) \)
- (b) \( 20x^2 - 4x = 4x(5x - 1) \)
- (c) \( -20x^2 - 15x^2 = -35x^2 \)
- (d) \( -6x + 4x^2 = 2x(2x - 3) \)
Quick Answer
- (a) \( 12x^2 + 9x = 3x(4x + 3) \)
- (b) \( 20x^2 - 4x = 4x(5x - 1) \)
- (c) \( -20x^2 - 15x^2 = -5x^2(7) \)
- (d) \( -6x + 4x^2 = 2x(2x - 3) \)
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