Find the center and radius of the circle. $$ (x-3)^{2}+(y+5)^{2}=16 $$ The center of the circle is (Type an ordered pair.)

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The center of the circle is $$(3, -5)$$. The equation of the circle is given in the standard form: $$ (x - h)^2 + (y - k)^2 = r^2 $$ where $$(h, k)$$ is the center of the circle and $$r$$ is the radius. From the equation: $$ (x - 3)^2 + (y + 5)^2 = 16 $$ we can identify the following: - $$h = 3$$ - $$k = -5$$ - $$r^2 = 16$$ To find the radius $$r$$, we take the square root of $$r^2$$: $$ r = \sqrt{16} = 4 $$ Thus, the center of the circle is: $$ (3, -5) $$ So, the center of the circle is $$\boxed{(3, -5)}$$.

Find the center and radius of the circle. \[ (x-3)^{2}+(y+5)^{2}=16 \] The center of the circle is (Type an ordered pair.)

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Find the center and radius of the circle. \[ (x-3)^{2}+(y+5)^{2}=16 \] The center of the circle is (Type an ordered pair.)

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