In the circuit shown, the reading of voltmeter is 8 V , so the value of the electric current intensity passes through the resistance \( 12 \Omega \) is: (A) 1.2 A (B) 0.8 A (C) 1.8 A (D) 2 A

Given: - Voltage reading of the voltmeter is 8 V. - Resistance is 12 Ω. We can use Ohm's Law to find the electric current intensity passing through the resistance. Ohm's Law states that the current passing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. Ohm's Law formula: \( I = \frac{V}{R} \) Substitute the given values: \( I = \frac{8}{12} \) Now, we can calculate the electric current intensity passing through the resistance. Calculate the value by following steps: - step0: Calculate: \(\frac{8}{12}\) - step1: Reduce the fraction: \(\frac{2}{3}\) The electric current intensity passing through the resistance is \( \frac{2}{3} \) A or approximately 0.6 A. Therefore, the closest option to this value is (B) 0.8 A.