Write 56 as a product of its prime factors

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$$ 56 = 2^3 \times 7 $$ To express 56 as a product of its prime factors, we can start by dividing it by the smallest prime number, which is 2. 1. $$ 56 \div 2 = 28 $$ 2. $$ 28 \div 2 = 14 $$ 3. $$ 14 \div 2 = 7 $$ Now, 7 is a prime number, so we stop here. Putting it all together, we have: $$ 56 = 2 \times 2 \times 2 \times 7 = 2^3 \times 7 $$ Thus, the prime factorization of 56 is $$ 2^3 \times 7 $$.

Write 56 as a product of its prime factors

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Write 56 as a product of its prime factors

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