Mckenzie Wells
01/20/2023 · High School
Find the equation of the tangents to the curve \( y=\cos x \) at \( x=-\pi, \frac{\pi}{2} \), and \( -\frac{3 \pi}{2} \). Graph the curve over the interval \( \left[-\frac{3 \pi}{2}, 2 \pi\right] \) together with their tangents. Label each curve and tangent. What is the equation of the tangent \( (1) \) to the curve at \( x=-\pi \) ? \( y=\square \)
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Step-by-step Solution
To find the equation of the tangent to the curve \( y = \cos x \) at a given point, we need to follow these steps:
1. **Find the derivative of the function** to determine the slope of the tangent line.
2. **Evaluate the function and the derivative at the specified point** to find the coordinates of the point of tangency and the slope.
3. **Use the point-slope form of the equation of a line** to write the equation of the tangent line.
### Step 1: Find the derivative
The derivative of \( y = \cos x \) is:
\[
\frac{dy}{dx} = -\sin x
\]
### Step 2: Evaluate at \( x = -\pi \)
1. **Find the function value**:
\[
y(-\pi) = \cos(-\pi) = -1
\]
2. **Find the slope**:
\[
\frac{dy}{dx} \bigg|_{x=-\pi} = -\sin(-\pi) = 0
\]
So, at the point \( (-\pi, -1) \), the slope of the tangent line is \( 0 \).
### Step 3: Write the equation of the tangent line
Using the point-slope form \( y - y_1 = m(x - x_1) \):
- Point: \( (-\pi, -1) \)
- Slope: \( 0 \)
The equation becomes:
\[
y - (-1) = 0(x - (-\pi))
\]
\[
y + 1 = 0
\]
\[
y = -1
\]
Thus, the equation of the tangent at \( x = -\pi \) is:
\[
y = -1
\]
### Summary
The equation of the tangent (1) to the curve at \( x = -\pi \) is:
\[
y = -1
\]
### Next Steps
To find the equations of the tangents at \( x = \frac{\pi}{2} \) and \( x = -\frac{3\pi}{2} \), we can follow the same steps:
#### For \( x = \frac{\pi}{2} \):
1. **Function value**:
\[
y\left(\frac{\pi}{2}\right) = \cos\left(\frac{\pi}{2}\right) = 0
\]
2. **Slope**:
\[
\frac{dy}{dx} \bigg|_{x=\frac{\pi}{2}} = -\sin\left(\frac{\pi}{2}\right) = -1
\]
3. **Equation**:
\[
y - 0 = -1\left(x - \frac{\pi}{2}\right)
\]
\[
y = -x + \frac{\pi}{2}
\]
#### For \( x = -\frac{3\pi}{2} \):
1. **Function value**:
\[
y\left(-\frac{3\pi}{2}\right) = \cos\left(-\frac{3\pi}{2}\right) = 0
\]
2. **Slope**:
\[
\frac{dy}{dx} \bigg|_{x=-\frac{3\pi}{2}} = -\sin\left(-\frac{3\pi}{2}\right) = 1
\]
3. **Equation**:
\[
y - 0 = 1\left(x + \frac{3\pi}{2}\right)
\]
\[
y = x + \frac{3\pi}{2}
\]
### Final Tangent Equations
1. At \( x = -\pi \): \( y = -1 \)
2. At \( x = \frac{\pi}{2} \): \( y = -x + \frac{\pi}{2} \)
3. At \( x = -\frac{3\pi}{2} \): \( y = x + \frac{3\pi}{2} \)
### Graphing
To graph the curve \( y = \cos x \) and the tangents over the interval \( \left[-\frac{3\pi}{2}, 2\pi\right] \), you can use graphing software or tools to visualize the function and the tangent lines. Each curve and tangent should be labeled accordingly.
Quick Answer
The equation of the tangent at \( x = -\pi \) is \( y = -1 \).
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