Lindsey Pearson
03/29/2024 · Senior High School

27. \( \int_{0}^{1}(u+2)(u-3) d u \)

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Calculate the integral \( \int_{0}^{1}(u+2)(u-3) du \). Evaluate the integral by following steps: - step0: Evaluate using formulas and rules: \(\int_{0}^{1} \left(u+2\right)\left(u-3\right) du\) - step1: Multiply the terms: \(\int_{0}^{1} u^{2}-u-6 du\) - step2: Evaluate the integral: \(\int u^{2}-u-6 du\) - step3: Use properties of integrals: \(\int u^{2} du-\int u du-\int 6 du\) - step4: Evaluate the integral: \(\frac{1}{3}u^{3}-\frac{1}{2}u^{2}-6u\) - step5: Return the limits: \(\left(\frac{1}{3}u^{3}-\frac{1}{2}u^{2}-6u\right)\bigg |_{0}^{1}\) - step6: Calculate the value: \(-\frac{37}{6}\) The result of the integral \( \int_{0}^{1}(u+2)(u-3) du \) is \( -\frac{37}{6} \) or \( -6\frac{1}{6} \) or \( -6.1\dot{6} \).

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El resultado de la integral \( \int_{0}^{1}(u+2)(u-3) du \) es \( -\frac{37}{6} \).
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