Lindsey Pearson
03/29/2024 · Senior High School
27. \( \int_{0}^{1}(u+2)(u-3) d u \)
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Step-by-step Solution
Calculate the integral \( \int_{0}^{1}(u+2)(u-3) du \).
Evaluate the integral by following steps:
- step0: Evaluate using formulas and rules:
\(\int_{0}^{1} \left(u+2\right)\left(u-3\right) du\)
- step1: Multiply the terms:
\(\int_{0}^{1} u^{2}-u-6 du\)
- step2: Evaluate the integral:
\(\int u^{2}-u-6 du\)
- step3: Use properties of integrals:
\(\int u^{2} du-\int u du-\int 6 du\)
- step4: Evaluate the integral:
\(\frac{1}{3}u^{3}-\frac{1}{2}u^{2}-6u\)
- step5: Return the limits:
\(\left(\frac{1}{3}u^{3}-\frac{1}{2}u^{2}-6u\right)\bigg |_{0}^{1}\)
- step6: Calculate the value:
\(-\frac{37}{6}\)
The result of the integral \( \int_{0}^{1}(u+2)(u-3) du \) is \( -\frac{37}{6} \) or \( -6\frac{1}{6} \) or \( -6.1\dot{6} \).
Quick Answer
El resultado de la integral \( \int_{0}^{1}(u+2)(u-3) du \) es \( -\frac{37}{6} \).
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