Shanon walked \( 1 \frac{2}{3} \) miles on Wednesday and \( 2 \frac{3}{5} \) miles on Thursday, What was the tatal disunce, in miles, Shanon walked during those 2 days?

To find the total distance Shanon walked on Wednesday and Thursday, we need to add the two distances together: \( 1 \frac{2}{3} \) miles and \( 2 \frac{3}{5} \) miles. First, we convert the mixed numbers into improper fractions. 1. For \( 1 \frac{2}{3} \): \[ 1 \frac{2}{3} = \frac{3 \times 1 + 2}{3} = \frac{3 + 2}{3} = \frac{5}{3} \] 2. For \( 2 \frac{3}{5} \): \[ 2 \frac{3}{5} = \frac{5 \times 2 + 3}{5} = \frac{10 + 3}{5} = \frac{13}{5} \] Now we need to add \( \frac{5}{3} \) and \( \frac{13}{5} \). To do this, we need a common denominator. The least common multiple of 3 and 5 is 15. Next, we convert each fraction to have a denominator of 15: 1. Convert \( \frac{5}{3} \): \[ \frac{5}{3} = \frac{5 \times 5}{3 \times 5} = \frac{25}{15} \] 2. Convert \( \frac{13}{5} \): \[ \frac{13}{5} = \frac{13 \times 3}{5 \times 3} = \frac{39}{15} \] Now we can add the two fractions: \[ \frac{25}{15} + \frac{39}{15} = \frac{25 + 39}{15} = \frac{64}{15} \] Finally, we can convert \( \frac{64}{15} \) back to a mixed number: \[ 64 \div 15 = 4 \quad \text{(with a remainder of 4)} \] So, \[ \frac{64}{15} = 4 \frac{4}{15} \] Thus, the total distance Shanon walked during those 2 days is: \[ \boxed{4 \frac{4}{15}} \text{ miles} \]