Brewer Rowe
07/16/2023 · Senior High School
Question 9 (Mandatory) (1 point) If a body goes from \( 10 \mathrm{~m} / \mathrm{s} \) to \( 50 \mathrm{~m} / \mathrm{s} \) in 8 seconds, what is its acceleration? \( 1.25 \mathrm{~m} / \mathrm{s} / \mathrm{s} \) \( 5 \mathrm{~m} / \mathrm{s} / \mathrm{s} \) \( 6.25 \mathrm{~m} / \mathrm{s} / \mathrm{s} \) \( 40 \mathrm{~m} / \mathrm{s} / \mathrm{s} \)
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Tutor-Verified Answer
Step-by-step Solution
To find the acceleration, we can use the formula for acceleration:
\[
a = \frac{\Delta v}{\Delta t}
\]
where:
- \( \Delta v \) is the change in velocity,
- \( \Delta t \) is the change in time.
In this case:
- The initial velocity \( v_i = 10 \, \text{m/s} \)
- The final velocity \( v_f = 50 \, \text{m/s} \)
- The time interval \( \Delta t = 8 \, \text{s} \)
First, we calculate the change in velocity:
\[
\Delta v = v_f - v_i = 50 \, \text{m/s} - 10 \, \text{m/s} = 40 \, \text{m/s}
\]
Now, we can calculate the acceleration:
\[
a = \frac{\Delta v}{\Delta t} = \frac{40 \, \text{m/s}}{8 \, \text{s}} = 5 \, \text{m/s}^2
\]
Thus, the acceleration is \( 5 \, \text{m/s}^2 \).
The correct answer is:
\( 5 \, \text{m/s} / \text{s} \)
Quick Answer
The acceleration is \( 5 \, \text{m/s}^2 \).
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