Davies Potter
12/22/2023 · Elementary School
Find the average rate of change of \( f \) from 0 to \( \frac{\pi}{9} \) \( f(x)=\tan (3 x) \) The average rate of change is (Simplify your answer, including any radicals. Type an exact answer, using \( \pi \) as needed.
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The average rate of change of a function \( f \) over an interval \([a, b]\) is given by the formula:
\[ \text{Average Rate of Change} = \frac{f(b) - f(a)}{b - a} \]
Given that \( f(x) = \tan(3x) \) and we want to find the average rate of change from 0 to \( \frac{\pi}{9} \), we can substitute these values into the formula and calculate the result.
1. Calculate \( f(0) \):
\[ f(0) = \tan(3 \times 0) = \tan(0) = 0 \]
2. Calculate \( f\left(\frac{\pi}{9}\right) \):
\[ f\left(\frac{\pi}{9}\right) = \tan\left(3 \times \frac{\pi}{9}\right) = \tan\left(\frac{\pi}{3}\right) = \sqrt{3} \]
3. Substitute the values into the formula for average rate of change:
\[ \text{Average Rate of Change} = \frac{f\left(\frac{\pi}{9}\right) - f(0)}{\frac{\pi}{9} - 0} = \frac{\sqrt{3} - 0}{\frac{\pi}{9}} = \frac{9\sqrt{3}}{\pi} \]
Therefore, the average rate of change of \( f \) from 0 to \( \frac{\pi}{9} \) is \( \frac{9\sqrt{3}}{\pi} \).
Quick Answer
The average rate of change is \( \frac{9\sqrt{3}}{\pi} \).
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