Wagner Brooks
10/10/2023 · Senior High School

Bonus 1 : Write each of the following expressions as a number with the indicated base. (a) \( 5 \times 2^{6}+15 \times 2^{2}-2^{2} \) (b) \( 7-5(10)+10000+9\left(10^{5}\right) \quad \) (base 10) Bonus 2 : Consider the expression \( \left(625 \cdot 5^{m+1}\right)^{n+1} \), where \( m \) and \( n \) are positive integers. (a) Simplify the expression. (b) If \( \left(625 \cdot 5^{m+1}\right)^{n+1}=25^{9} \), find all possible values of \( m \) and \( n \).

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### 額外題 1: (a) 將表達式 \( 5 \times 2^{6}+15 \times 2^{2}-2^{2} \) 轉換為二進制數: \[ 376_{10} = 101111000_{2} \] (b) 將表達式 \( 7-5(10)+10000+9\left(10^{5}\right) \) 轉換為十進制數: \[ 90957 \] ### 額外題 2: (a) 簡化表達式 \( \left(625 \cdot 5^{m+1}\right)^{n+1} \): \[ 5^{(m+5)(n+1)} \] (b) 如果 \( \left(625 \cdot 5^{m+1}\right)^{n+1}=25^{9} \),則所有可能的正整數解為: - \( (m, n) = (1, 2) \) - \( (m, n) = (4, 1) \)

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