Wagner Brooks
10/10/2023 · Senior High School
Bonus 1 : Write each of the following expressions as a number with the indicated base. (a) \( 5 \times 2^{6}+15 \times 2^{2}-2^{2} \) (b) \( 7-5(10)+10000+9\left(10^{5}\right) \quad \) (base 10) Bonus 2 : Consider the expression \( \left(625 \cdot 5^{m+1}\right)^{n+1} \), where \( m \) and \( n \) are positive integers. (a) Simplify the expression. (b) If \( \left(625 \cdot 5^{m+1}\right)^{n+1}=25^{9} \), find all possible values of \( m \) and \( n \).
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### 額外題 1:
(a) 將表達式 \( 5 \times 2^{6}+15 \times 2^{2}-2^{2} \) 轉換為二進制數:
\[
376_{10} = 101111000_{2}
\]
(b) 將表達式 \( 7-5(10)+10000+9\left(10^{5}\right) \) 轉換為十進制數:
\[
90957
\]
### 額外題 2:
(a) 簡化表達式 \( \left(625 \cdot 5^{m+1}\right)^{n+1} \):
\[
5^{(m+5)(n+1)}
\]
(b) 如果 \( \left(625 \cdot 5^{m+1}\right)^{n+1}=25^{9} \),則所有可能的正整數解為:
- \( (m, n) = (1, 2) \)
- \( (m, n) = (4, 1) \)
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