Peterson Frank
10/07/2024 · Elementary School
thout using calculator, prove that : \( \tan ^{2} 60^{\circ}-\tan ^{2} 45^{\circ}=4 \sin 30^{\circ} \)
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لنبدأ بإيجاد قيم الزوايا المعطاة:
1. **حساب \( \tan 60^{\circ} \)**:
\[
\tan 60^{\circ} = \sqrt{3}
\]
وبالتالي:
\[
\tan^2 60^{\circ} = 3
\]
2. **حساب \( \tan 45^{\circ} \)**:
\[
\tan 45^{\circ} = 1
\]
وبالتالي:
\[
\tan^2 45^{\circ} = 1
\]
3. **الآن نحسب الفرق**:
\[
\tan^2 60^{\circ} - \tan^2 45^{\circ} = 2
\]
4. **حساب \( 4 \sin 30^{\circ} \)**:
\[
\sin 30^{\circ} = \frac{1}{2}
\]
وبالتالي:
\[
4 \sin 30^{\circ} = 2
\]
5. **الآن نقارن النتائج**:
\[
\tan^2 60^{\circ} - \tan^2 45^{\circ} = 2
\]
و
\[
4 \sin 30^{\circ} = 2
\]
لذا، يمكننا أن نستنتج أن:
\[
\tan^2 60^{\circ} - \tan^2 45^{\circ} = 4 \sin 30^{\circ}
\]
وبذلك، تم إثبات المعادلة المطلوبة.
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