Peterson Frank
10/07/2024 · Elementary School

thout using calculator, prove that : \( \tan ^{2} 60^{\circ}-\tan ^{2} 45^{\circ}=4 \sin 30^{\circ} \)

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لنبدأ بإيجاد قيم الزوايا المعطاة: 1. **حساب \( \tan 60^{\circ} \)**: \[ \tan 60^{\circ} = \sqrt{3} \] وبالتالي: \[ \tan^2 60^{\circ} = 3 \] 2. **حساب \( \tan 45^{\circ} \)**: \[ \tan 45^{\circ} = 1 \] وبالتالي: \[ \tan^2 45^{\circ} = 1 \] 3. **الآن نحسب الفرق**: \[ \tan^2 60^{\circ} - \tan^2 45^{\circ} = 2 \] 4. **حساب \( 4 \sin 30^{\circ} \)**: \[ \sin 30^{\circ} = \frac{1}{2} \] وبالتالي: \[ 4 \sin 30^{\circ} = 2 \] 5. **الآن نقارن النتائج**: \[ \tan^2 60^{\circ} - \tan^2 45^{\circ} = 2 \] و \[ 4 \sin 30^{\circ} = 2 \] لذا، يمكننا أن نستنتج أن: \[ \tan^2 60^{\circ} - \tan^2 45^{\circ} = 4 \sin 30^{\circ} \] وبذلك، تم إثبات المعادلة المطلوبة.

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