Warner Welch
03/31/2024 · Junior High School
\( \left. \begin{array} { | c | } \hline 12 : 15 \\ \hline 20 : 25 \\ \hline 32 : 60 \\ \hline \end{array} \right. \)
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Step-by-step Solution
It looks like you have provided a table with ratios. Let's analyze the ratios given:
1. \( 12 : 15 \)
2. \( 20 : 25 \)
3. \( 32 : 60 \)
To simplify these ratios, we can divide both sides of each ratio by their greatest common divisor (GCD).
1. For \( 12 : 15 \):
- The GCD of 12 and 15 is 3.
- Simplifying gives \( \frac{12}{3} : \frac{15}{3} = 4 : 5 \).
2. For \( 20 : 25 \):
- The GCD of 20 and 25 is 5.
- Simplifying gives \( \frac{20}{5} : \frac{25}{5} = 4 : 5 \).
3. For \( 32 : 60 \):
- The GCD of 32 and 60 is 4.
- Simplifying gives \( \frac{32}{4} : \frac{60}{4} = 8 : 15 \).
Now, we can summarize the simplified ratios:
- \( 12 : 15 \) simplifies to \( 4 : 5 \)
- \( 20 : 25 \) simplifies to \( 4 : 5 \)
- \( 32 : 60 \) simplifies to \( 8 : 15 \)
If you have a specific question or need further analysis regarding these ratios, please let me know!
Quick Answer
- \( 12 : 15 \) simplifies to \( 4 : 5 \)
- \( 20 : 25 \) simplifies to \( 4 : 5 \)
- \( 32 : 60 \) simplifies to \( 8 : 15 \)
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