Black West
10/16/2023 · Junior High School
A train moves with velocity \( +10.0 \mathrm{~m} / \mathrm{s} \) for 15.0 s .
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Step-by-step Solution
To analyze the motion of the train, we can use the basic kinematic equations. Given that the train moves with a constant velocity of \( +10.0 \, \text{m/s} \) for a time duration of \( 15.0 \, \text{s} \), we can calculate the distance traveled by the train during this time.
The formula to calculate distance (\( d \)) when velocity (\( v \)) and time (\( t \)) are known is:
\[
d = v \cdot t
\]
Substituting the given values:
\[
d = (10.0 \, \text{m/s}) \cdot (15.0 \, \text{s}) = 150.0 \, \text{m}
\]
Thus, the train travels a distance of \( 150.0 \, \text{m} \) in \( 15.0 \, \text{s} \).
If you have any further questions or need additional calculations, feel free to ask!
Quick Answer
The train travels 150.0 meters in 15.0 seconds.
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