Find the following matries where $$ A=\left[\begin{array}{cc}6 & -7 \ -4 & 6 \ -1 & 4\end{array}\right] \text { and } $$ $$ B=\left[\begin{array}{cc}-9 & 8 \ 3 & 0 \ -3 & 8\end{array}\right] $$ Select the correct choice below $$ O $$ A. A-B $$ =\square $$ simplify your answer $$ O B $$. This matrice operation is nit passi

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$$ \begin{bmatrix} 15 & -15 \ -7 & 6 \ 2 & -4 \end{bmatrix} $$ To find the matrix $$ A - B $$, we need to ensure that both matrices $$ A $$ and $$ B $$ have the same dimensions. Matrix $$ A $$ is a $$ 3 \times 2 $$ matrix: $$ A = \begin{bmatrix} 6 & -7 \ -4 & 6 \ -1 & 4 \end{bmatrix} $$ Matrix $$ B $$ is also a $$ 3 \times 2 $$ matrix: $$ B = \begin{bmatrix} -9 & 8 \ 3 & 0 \ -3 & 8 \end{bmatrix} $$ Since both matrices have the same dimensions, we can perform the subtraction $$ A - B $$. To subtract the matrices, we subtract the corresponding elements: $$ A - B = \begin{bmatrix} 6 - (-9) & -7 - 8 \ -4 - 3 & 6 - 0 \ -1 - (-3) & 4 - 8 \end{bmatrix} $$ Calculating each element: 1. First row: - $$ 6 - (-9) = 6 + 9 = 15 $$ - $$ -7 - 8 = -15 $$ 2. Second row: - $$ -4 - 3 = -7 $$ - $$ 6 - 0 = 6 $$ 3. Third row: - $$ -1 - (-3) = -1 + 3 = 2 $$ - $$ 4 - 8 = -4 $$ Putting it all together, we get: $$ A - B = \begin{bmatrix} 15 & -15 \ -7 & 6 \ 2 & -4 \end{bmatrix} $$ Thus, the simplified answer for $$ A - B $$ is: $$ \begin{bmatrix} 15 & -15 \ -7 & 6 \ 2 & -4 \end{bmatrix} $$

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