Pierce Wood
07/12/2023 · High School

Evaluate \( \int \sec (11+12 x) \cdot \tan (11+12 x) d x \)

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Step-by-step Solution

Calculate the integral \( \int \sec (11+12 x) \cdot \tan (11+12 x) d x \). Evaluate the integral by following steps: - step0: Evaluate using substitution: \(\int \sec\left(11+12x\right)\tan\left(11+12x\right) dx\) - step1: Rewrite the expression: \(\int \sec\left(12x+11\right)\tan\left(11+12x\right) dx\) - step2: Rewrite the expression: \(\int \sec\left(12x+11\right)\tan\left(12x+11\right) dx\) - step3: Rewrite the expression: \(\int \cos^{-2}\left(12x+11\right)\sin\left(12x+11\right) dx\) - step4: Use the substitution \(dx=-\frac{1}{12\sin\left(12x+11\right)} dt\) to transform the integral\(:\) \(\int \cos^{-2}\left(12x+11\right)\sin\left(12x+11\right)\left(-\frac{1}{12\sin\left(12x+11\right)}\right) dt\) - step5: Simplify: \(\int -\frac{1}{12}\cos^{-2}\left(12x+11\right) dt\) - step6: Use the substitution \(t=\cos\left(12x+11\right)\) to transform the integral\(:\) \(\int -\frac{1}{12}t^{-2} dt\) - step7: Use properties of integrals: \(-\frac{1}{12}\times \int t^{-2} dt\) - step8: Evaluate the integral: \(-\frac{1}{12}\left(-t^{-1}\right)\) - step9: Calculate: \(\frac{1}{12}t^{-1}\) - step10: Substitute back: \(\frac{1}{12}\cos^{-1}\left(12x+11\right)\) - step11: Simplify: \(\frac{1}{12}\sec\left(12x+11\right)\) - step12: Add the constant of integral C: \(\frac{1}{12}\sec\left(12x+11\right) + C, C \in \mathbb{R}\) The result of the integral \( \int \sec (11+12 x) \cdot \tan (11+12 x) d x \) is \( \frac{1}{12}\sec(12x+11) + C \), where \( C \) is an arbitrary constant.

Quick Answer

\( \frac{1}{12}\sec(12x+11) + C \)
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