If \( h \sin ^{2} \theta \) \( 2 \sec ^{2} \theta_{2} \) \( |b|=\frac{\sqrt{2 c h}}{2} \)

Given: - \( h \sin ^{2} \theta \) - \( 2 \sec ^{2} \theta_{2} \) - \( |b|=\frac{\sqrt{2 c h}}{2} \) We need to simplify the expressions and find the value of \( |b| \). Let's start by simplifying the expressions: 1. \( h \sin ^{2} \theta \) 2. \( 2 \sec ^{2} \theta_{2} \) For the first expression, we can use the trigonometric identity \( \sin ^{2} \theta = 1 - \cos ^{2} \theta \) to simplify it. \( h \sin ^{2} \theta = h(1 - \cos ^{2} \theta) \) For the second expression, we can use the trigonometric identity \( \sec ^{2} \theta = 1 + \tan ^{2} \theta \) to simplify it. \( 2 \sec ^{2} \theta_{2} = 2(1 + \tan ^{2} \theta_{2}) \) Now, let's find the value of \( |b| \) using the given equation \( |b|=\frac{\sqrt{2 c h}}{2} \). Substitute the simplified expressions into the equation: \( |b| = \frac{\sqrt{2 c h}}{2} \) Now, we can simplify this expression to find the value of \( |b| \).