Write the following sum as a single logarithm. Assume all variables are positive. $$ \log _{3}(4)+\log _{3}(b)=\square $$ Preview

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$$\log_{3}(4b)$$ To combine the logarithms $$ \log_{3}(4) + \log_{3}(b) $$ into a single logarithm, we can use the property of logarithms that states: $$ \log_{a}(m) + \log_{a}(n) = \log_{a}(m \cdot n) $$ Applying this property to our expression: $$ \log_{3}(4) + \log_{3}(b) = \log_{3}(4 \cdot b) $$ Thus, the sum can be written as a single logarithm: $$ \log_{3}(4b) $$ So, the final answer is: $$ \log_{3}(4b) $$

Write the following sum as a single logarithm. Assume all variables are positive. \( \log _{3}(4)+\log _{3}(b)=\square \) Preview

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Write the following sum as a single logarithm. Assume all variables are positive. \( \log _{3}(4)+\log _{3}(b)=\square \) Preview

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