Stuart John
07/23/2023 · Junior High School
Compute each of the following and compare. \( 1^{2}+1^{2} \quad(1+1)^{2} \) \( 1^{2}+1^{2}=\square \)
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Tutor-Verified Answer
Step-by-step Solution
Let's compute each expression step by step.
1. For \( 1^{2} + 1^{2} \):
\[
1^{2} = 1
\]
Therefore,
\[
1^{2} + 1^{2} = 1 + 1 = 2
\]
2. For \( (1 + 1)^{2} \):
\[
1 + 1 = 2
\]
Now, we compute \( 2^{2} \):
\[
2^{2} = 4
\]
Now we can compare the results:
- \( 1^{2} + 1^{2} = 2 \)
- \( (1 + 1)^{2} = 4 \)
Thus, we have:
\[
1^{2} + 1^{2} = 2 \quad \text{and} \quad (1 + 1)^{2} = 4
\]
In conclusion:
\[
1^{2} + 1^{2} = 2 \quad \text{and} \quad (1 + 1)^{2} = 4
\]
Quick Answer
\( 1^{2} + 1^{2} = 2 \)
\( (1 + 1)^{2} = 4 \)
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