Potter Blake
07/15/2023 · Elementary School
\( \omega=f(c, v), u=x+y, v=x-y \), show that \( \frac{\partial u}{\partial x} \frac{2 w}{\partial y}=\left(\frac{3 w}{b y}\right)^{2}-\left(\frac{0 w}{0 u}\right)^{2} \)
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Tutor-Verified Answer
Step-by-step Solution
To show the equation
\[
\frac{\partial u}{\partial x} \frac{2 w}{\partial y} = \left(\frac{3 w}{b y}\right)^{2} - \left(\frac{0 w}{0 u}\right)^{2},
\]
we first need to analyze the components of the equation.
1. **Understanding the Variables**:
- We have \( u = x + y \) and \( v = x - y \).
- The function \( \omega = f(c, v) \) suggests that \( \omega \) depends on some variables \( c \) and \( v \).
2. **Calculating Partial Derivatives**:
- The partial derivative of \( u \) with respect to \( x \) is:
\[
\frac{\partial u}{\partial x} = \frac{\partial (x + y)}{\partial x} = 1.
\]
3. **Finding \( \frac{\partial w}{\partial y} \)**:
- To find \( \frac{\partial w}{\partial y} \), we need to express \( w \) in terms of \( y \). Since \( w \) is a function of \( c \) and \( v \), we need to know how \( c \) relates to \( y \) and \( v \). However, without additional information about \( c \), we cannot compute \( \frac{\partial w}{\partial y} \) directly.
4. **Analyzing the Right Side of the Equation**:
- The term \( \left(\frac{0 w}{0 u}\right)^{2} \) is problematic because it suggests a division by zero, which is undefined. This indicates that the right-hand side of the equation may not be well-defined unless \( w \) or \( u \) is zero.
5. **Simplifying the Equation**:
- The left-hand side simplifies to:
\[
\frac{\partial u}{\partial x} \frac{2 w}{\partial y} = 1 \cdot \frac{2 w}{\partial y} = \frac{2 w}{\partial y}.
\]
- The right-hand side simplifies to:
\[
\left(\frac{3 w}{b y}\right)^{2} - \left(\frac{0 w}{0 u}\right)^{2} = \left(\frac{3 w}{b y}\right)^{2} - \text{undefined}.
\]
6. **Conclusion**:
- The equation as presented cannot be shown to hold true without additional context or definitions for \( w \), \( c \), and how they relate to \( y \) and \( u \). The presence of \( \left(\frac{0 w}{0 u}\right)^{2} \) suggests that there may be a mistake or a need for clarification in the formulation of the problem.
In summary, without further information or context, we cannot demonstrate the validity of the equation as it stands.
Quick Answer
The equation cannot be shown to hold true without additional information about the variables \( w \), \( c \), and their relationships with \( y \) and \( u \). The presence of \( \left(\frac{0 w}{0 u}\right)^{2} \) indicates a potential issue with the formulation of the problem.
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