King Bond
09/23/2023 · Middle School

Which function is the inverse of \( g(x)=2 \sqrt[3]{x-3}+4 \) ? \( f(x)=\frac{(x-4)^{3}}{8}+3 \) \( f(x)=\frac{(x-2)^{3}}{64}+3 \) \( f(x)=\frac{(x-4)^{3}}{2}+3 \) \( f(x)=\frac{(x-2)^{3}}{4}+3 \)

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Step-by-step Solution

To find the inverse of the function \( g(x) = 2 \sqrt[3]{x-3} + 4 \), we will follow these steps: 1. Replace \( g(x) \) with \( y \): \[ y = 2 \sqrt[3]{x-3} + 4 \] 2. Solve for \( x \) in terms of \( y \): \[ y - 4 = 2 \sqrt[3]{x-3} \] \[ \frac{y - 4}{2} = \sqrt[3]{x-3} \] Now, cube both sides: \[ \left( \frac{y - 4}{2} \right)^3 = x - 3 \] \[ x = \left( \frac{y - 4}{2} \right)^3 + 3 \] 3. Now, replace \( y \) with \( x \) to express the inverse function: \[ g^{-1}(x) = \left( \frac{x - 4}{2} \right)^3 + 3 \] 4. Simplify the expression: \[ g^{-1}(x) = \frac{(x - 4)^3}{8} + 3 \] Now, we can compare this result with the given options: - \( f(x) = \frac{(x-4)^{3}}{8}+3 \) - \( f(x) = \frac{(x-2)^{3}}{64}+3 \) - \( f(x) = \frac{(x-4)^{3}}{2}+3 \) - \( f(x) = \frac{(x-2)^{3}}{4}+3 \) The correct inverse function is: \[ \boxed{f(x) = \frac{(x-4)^{3}}{8}+3} \]

Quick Answer

The inverse function is \( f(x) = \frac{(x-4)^{3}}{8}+3 \).
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