King Bond
09/23/2023 · Middle School
Which function is the inverse of \( g(x)=2 \sqrt[3]{x-3}+4 \) ? \( f(x)=\frac{(x-4)^{3}}{8}+3 \) \( f(x)=\frac{(x-2)^{3}}{64}+3 \) \( f(x)=\frac{(x-4)^{3}}{2}+3 \) \( f(x)=\frac{(x-2)^{3}}{4}+3 \)
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
To find the inverse of the function \( g(x) = 2 \sqrt[3]{x-3} + 4 \), we will follow these steps:
1. Replace \( g(x) \) with \( y \):
\[
y = 2 \sqrt[3]{x-3} + 4
\]
2. Solve for \( x \) in terms of \( y \):
\[
y - 4 = 2 \sqrt[3]{x-3}
\]
\[
\frac{y - 4}{2} = \sqrt[3]{x-3}
\]
Now, cube both sides:
\[
\left( \frac{y - 4}{2} \right)^3 = x - 3
\]
\[
x = \left( \frac{y - 4}{2} \right)^3 + 3
\]
3. Now, replace \( y \) with \( x \) to express the inverse function:
\[
g^{-1}(x) = \left( \frac{x - 4}{2} \right)^3 + 3
\]
4. Simplify the expression:
\[
g^{-1}(x) = \frac{(x - 4)^3}{8} + 3
\]
Now, we can compare this result with the given options:
- \( f(x) = \frac{(x-4)^{3}}{8}+3 \)
- \( f(x) = \frac{(x-2)^{3}}{64}+3 \)
- \( f(x) = \frac{(x-4)^{3}}{2}+3 \)
- \( f(x) = \frac{(x-2)^{3}}{4}+3 \)
The correct inverse function is:
\[
\boxed{f(x) = \frac{(x-4)^{3}}{8}+3}
\]
Quick Answer
The inverse function is \( f(x) = \frac{(x-4)^{3}}{8}+3 \).
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