Greene Fernandez
05/07/2023 · Senior High School
Question 12 (Mandatory) (1 point) If an object is moving with a velocity of \( 24 \mathrm{~m} / \mathrm{s} \) and has an acceleration of \( -4 \mathrm{~m} / \mathrm{s} / \mathrm{s} \), how long will it take it to stop? -96 s -6 s -6 m 6 s
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Step-by-step Solution
To find out how long it will take for the object to stop, we can use the formula for acceleration:
\[
v_f = v_i + a \cdot t
\]
where:
- \( v_f \) is the final velocity (0 m/s when the object stops),
- \( v_i \) is the initial velocity (24 m/s),
- \( a \) is the acceleration (-4 m/s²),
- \( t \) is the time in seconds.
Setting \( v_f \) to 0, we can rearrange the equation to solve for \( t \):
\[
0 = 24 \, \text{m/s} + (-4 \, \text{m/s}^2) \cdot t
\]
This simplifies to:
\[
0 = 24 - 4t
\]
Now, solving for \( t \):
\[
4t = 24
\]
\[
t = \frac{24}{4} = 6 \, \text{s}
\]
So, it will take **6 seconds** for the object to stop.
The correct answer is **6 s**.
Quick Answer
It will take 6 seconds for the object to stop.
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