Greene Fernandez
05/07/2023 · Senior High School

Question 12 (Mandatory) (1 point) If an object is moving with a velocity of \( 24 \mathrm{~m} / \mathrm{s} \) and has an acceleration of \( -4 \mathrm{~m} / \mathrm{s} / \mathrm{s} \), how long will it take it to stop? -96 s -6 s -6 m 6 s

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To find out how long it will take for the object to stop, we can use the formula for acceleration: \[ v_f = v_i + a \cdot t \] where: - \( v_f \) is the final velocity (0 m/s when the object stops), - \( v_i \) is the initial velocity (24 m/s), - \( a \) is the acceleration (-4 m/s²), - \( t \) is the time in seconds. Setting \( v_f \) to 0, we can rearrange the equation to solve for \( t \): \[ 0 = 24 \, \text{m/s} + (-4 \, \text{m/s}^2) \cdot t \] This simplifies to: \[ 0 = 24 - 4t \] Now, solving for \( t \): \[ 4t = 24 \] \[ t = \frac{24}{4} = 6 \, \text{s} \] So, it will take **6 seconds** for the object to stop. The correct answer is **6 s**.

Quick Answer

It will take 6 seconds for the object to stop.
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