Salazar Pope
03/24/2023 · Senior High School
A) \( 3 x+6=2 x-4 \) B) \( 5(x-3)=30 \) (i) \( \sqrt{8 x+40}=8 \)
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Step-by-step Solution
Vamos a resolver cada una de las ecuaciones paso a paso.
A) \( 3x + 6 = 2x - 4 \)
1. Restamos \( 2x \) de ambos lados:
\[
3x - 2x + 6 = -4
\]
\[
x + 6 = -4
\]
2. Restamos 6 de ambos lados:
\[
x = -4 - 6
\]
\[
x = -10
\]
B) \( 5(x - 3) = 30 \)
1. Dividimos ambos lados entre 5:
\[
x - 3 = 6
\]
2. Sumamos 3 a ambos lados:
\[
x = 6 + 3
\]
\[
x = 9
\]
(i) \( \sqrt{8x + 40} = 8 \)
1. Elevamos al cuadrado ambos lados para eliminar la raíz:
\[
8x + 40 = 64
\]
2. Restamos 40 de ambos lados:
\[
8x = 64 - 40
\]
\[
8x = 24
\]
3. Dividimos ambos lados entre 8:
\[
x = \frac{24}{8}
\]
\[
x = 3
\]
Resumiendo:
- A) \( x = -10 \)
- B) \( x = 9 \)
- (i) \( x = 3 \)
Quick Answer
- A) \( x = -10 \)
- B) \( x = 9 \)
- (i) \( x = 3 \)
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