Find the center and radius of the circle. $$ (x-6)^{2}+(y+9)^{2}=11 $$ The center of the circle is $$ (6,-9) $$. (Type an ordered pair.) The radius is $$ \square $$. (Simplify your answer. Type an exact answer, using radicals as needed.)

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The center is $$(6, -9)$$ and the radius is $$\sqrt{11}$$. The equation of the circle is given by $$ (x-6)^{2}+(y+9)^{2}=11. $$ In the standard form of a circle's equation, $$(x-h)^{2}+(y-k)^{2}=r^{2}$$, the center of the circle is $$(h, k)$$ and the radius is $$r$$. From the given equation: - The center $$(h, k)$$ can be identified as: - $$h = 6$$ - $$k = -9$$ Thus, the center of the circle is $$ (6, -9). $$ Next, to find the radius, we note that $$r^{2} = 11$$. To find $$r$$, we take the square root: $$ r = \sqrt{11}. $$ Therefore, the radius of the circle is $$ \sqrt{11}. $$ In summary: - The center of the circle is $$(6, -9)$$. - The radius is $$\sqrt{11}$$.

Find the center and radius of the circle. \[ (x-6)^{2}+(y+9)^{2}=11 \] The center of the circle is \( (6,-9) \). (Type an ordered pair.) The radius is \( \square \). (Simplify your answer. Type an exact answer, using radicals as needed.)

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Find the center and radius of the circle. \[ (x-6)^{2}+(y+9)^{2}=11 \] The center of the circle is \( (6,-9) \). (Type an ordered pair.) The radius is \( \square \). (Simplify your answer. Type an exact answer, using radicals as needed.)

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