Hill Crawford
04/23/2023 · Primary School
\( c = \frac { - 4 \pm \sqrt { 4 ^ { 2 } - 4 ( 6 ) ( 4 ) } } { 2 ( 6 ) } \)
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
To solve the expression
\[
c = \frac{-4 \pm \sqrt{4^2 - 4(6)(4)}}{2(6)},
\]
we will first simplify the expression inside the square root.
1. Calculate \(4^2\):
\[
4^2 = 16.
\]
2. Calculate \(4(6)(4)\):
\[
4(6)(4) = 96.
\]
3. Now substitute these values back into the expression under the square root:
\[
4^2 - 4(6)(4) = 16 - 96 = -80.
\]
4. Now substitute this back into the equation for \(c\):
\[
c = \frac{-4 \pm \sqrt{-80}}{12}.
\]
5. Simplify \(\sqrt{-80}\):
\[
\sqrt{-80} = \sqrt{80} \cdot i = \sqrt{16 \cdot 5} \cdot i = 4\sqrt{5} \cdot i.
\]
6. Substitute this back into the equation for \(c\):
\[
c = \frac{-4 \pm 4\sqrt{5}i}{12}.
\]
7. Simplify the fraction:
\[
c = \frac{-4}{12} \pm \frac{4\sqrt{5}i}{12} = -\frac{1}{3} \pm \frac{\sqrt{5}}{3}i.
\]
Thus, the final result is:
\[
c = -\frac{1}{3} \pm \frac{\sqrt{5}}{3}i.
\]
Quick Answer
\[
c = -\frac{1}{3} \pm \frac{\sqrt{5}}{3}i.
\]
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