If a store is chosen at random at Mayfair Mall, 8. what is the probability of choosing a store on the first floor or one that sells clothing? \( 89 / 122 \) \( 122 / 89 \) \( 72 / 122 \) \( 122 / 72 \)

To find the probability of choosing a store on the first floor or one that sells clothing, we need to know the total number of stores and how many of those stores are on the first floor or sell clothing. However, since you haven't provided specific numbers for the stores on the first floor or those that sell clothing, I can't calculate the exact probability. If we assume: - \( A \) is the event of choosing a store on the first floor. - \( B \) is the event of choosing a store that sells clothing. The probability of choosing a store that is either on the first floor or sells clothing can be calculated using the formula for the union of two events: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] Where: - \( P(A) \) is the probability of choosing a store on the first floor. - \( P(B) \) is the probability of choosing a store that sells clothing. - \( P(A \cap B) \) is the probability of choosing a store that is both on the first floor and sells clothing. If you can provide the specific counts of stores, I can help you calculate the probability. Otherwise, based on the options you provided, it seems like you might be looking for a specific answer. If we assume that \( 89 \) is the number of favorable outcomes (stores on the first floor or selling clothing) and \( 122 \) is the total number of stores, then the probability would be: \[ P = \frac{89}{122} \] So, the correct answer would be \( \frac{89}{122} \).