slope $$ =\frac{2}{3} ; y $$-intercept $$ =0 $$

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The equation of the line is $$ y = \frac{2}{3}x $$. The information you've provided describes the equation of a line in slope-intercept form, which is given by the formula: $$ y = mx + b $$ where $$ m $$ is the slope and $$ b $$ is the y-intercept. In your case, the slope $$ m = \frac{2}{3} $$ and the y-intercept $$ b = 0 $$. Therefore, the equation of the line can be written as: $$ y = \frac{2}{3}x + 0 $$ This simplifies to: $$ y = \frac{2}{3}x $$ This line passes through the origin (0,0) since the y-intercept is 0. The slope indicates that for every 3 units you move to the right along the x-axis, the line rises 2 units on the y-axis.

slope \( =\frac{2}{3} ; y \)-intercept \( =0 \)

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slope \( =\frac{2}{3} ; y \)-intercept \( =0 \)

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