Find $$f(g(-1))$$ if $$f(x) = 5 - x$$ and $$g(x) = -x^2$$.

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$$f(g(-1)) = 6$$ To find $$f(g(-1))$$, we need to follow these steps: 1. Find $$g(-1)$$ by substituting $$-1$$ into the function $$g(x)$$. 2. Find $$f(g(-1))$$ by substituting the result from step 1 into the function $$f(x)$$. Let's start with step 1: $$g(x) = -x^2$$ Substitute $$-1$$ for $$x$$: $$g(-1) = -(-1)^2$$ $$g(-1) = -1$$ Now we have the result from step 1, we can move on to step 2: $$f(x) = 5 - x$$ Substitute $$-1$$ for $$x$$ (which is the result from step 1): $$f(g(-1)) = f(-1)$$ $$f(-1) = 5 - (-1)$$ $$f(-1) = 5 + 1$$ $$f(-1) = 6$$ So, $$f(g(-1)) = 6$$.

Find \(f(g(-1))\) if \(f(x) = 5 - x\) and \(g(x) = -x^2\).

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Find \(f(g(-1))\) if \(f(x) = 5 - x\) and \(g(x) = -x^2\).

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