function \( f(x)=2 x^{2}-9 x+5.7 \) Round

To round the function \( f(x) = 2x^2 - 9x + 5.7 \), we first need to evaluate it at a specific value of \( x \). However, since you haven't provided a specific value for \( x \), I will demonstrate how to evaluate and round the function for a few example values of \( x \). 1. **For \( x = 0 \)**: \[ f(0) = 2(0)^2 - 9(0) + 5.7 = 5.7 \] Rounding \( 5.7 \) gives \( 6 \). 2. **For \( x = 1 \)**: \[ f(1) = 2(1)^2 - 9(1) + 5.7 = 2 - 9 + 5.7 = -1.3 \] Rounding \( -1.3 \) gives \( -1 \). 3. **For \( x = 2 \)**: \[ f(2) = 2(2)^2 - 9(2) + 5.7 = 8 - 18 + 5.7 = -4.3 \] Rounding \( -4.3 \) gives \( -4 \). 4. **For \( x = 3 \)**: \[ f(3) = 2(3)^2 - 9(3) + 5.7 = 18 - 27 + 5.7 = -3.3 \] Rounding \( -3.3 \) gives \( -3 \). 5. **For \( x = 4 \)**: \[ f(4) = 2(4)^2 - 9(4) + 5.7 = 32 - 36 + 5.7 = 1.7 \] Rounding \( 1.7 \) gives \( 2 \). If you have a specific value of \( x \) in mind or a specific context for rounding, please let me know!