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Dickson Chadwick

11/05/2020 · Junior High School

Use the given minimum and maximum data entries, and the number of classes, to find the class width, the lower class limits, and the upper class limits. Please type them as whole numbers.

 

1. 

Minimum = 12, maximum =79, 6 classes 

The class width is___ 

Choose the correct lower class limits below: 

A. 23, 35, 48, 59, 71, 83 

B. 24, 35, 48, 60, 72, 83 

C. 12, 24, 36, 48, 60, 72 

D. 12, 23, 36, 47, 59, 72 

Choose the correct lower class limits below: 

A. 23, 35, 48, 60, 71, 83 

B. 24, 36, 47, 59, 72, 83 

C. 23, 35, 47, 59, 71, 83 

D. 24, 36, 48, 60, 72, 83

 

2. 

Minimum = 8, maximum = 72, 6 classes 

The class width is___ 

Choose the correct lower class limits below: 

A. 8, 18, 30, 40, 51, 63 

B. 19, 29, 41, 52, 63, 73 

C. 18, 29, 41, 51, 62, 73 

D. 8, 19, 30, 41, 52, 63 

Choose the correct lower class limits below: 

A. 19, 30, 40, 51, 63, 73 

B. 18, 29, 40, 51, 62, 73 

C. 18, 29, 41, 52, 62, 73 

D. 19, 30, 41, 52, 63, 73

 

3. 

Minimum = 15, Maximum = 9, Number of classes = 8 

The class width is ___ 

Choose the correct lower class limits below: 

A. 15, 26, 37, 48, 59, 70, 81, 92 

B. 15, 25, 35, 45, 55, 65, 75, 85 

C. 16, 27, 38, 49, 60, 71, 82, 93 

D. 14, 24, 34, 44, 54, 64, 74, 84 

Choose the correct upper class limits below: 

A. 25, 35, 45, 55, 65, 75, 85, 95 

B. 24, 34, 44, 54, 64, 74, 84, 94 

C. 23, 33, 43, 53, 63, 73, 83, 93 

D. 22, 32, 42, 52, 62, 72, 82, 92

Answer
expertExpert-Verified Answer

Tran Vargas
Competent Tutor
5.0 (33votes)

Part 1

 

Given:

- Minimum = 12

- Maximum = 79

- Number of classes = 6

 

Step-by-Step Solution:

1. Calculate the Range:

\[\text { Range} = \text { Maximum} - \text { Minimum} = 79 - 12 = 67\]

 

2. Calculate the Class Width:

\[\text { Class Width} = \frac { \text { Range} } { \text { Number of Classes} } \]

 

Since we want the class width as a whole number, we round up:

 

\[\text { Class Width} = \left \lceil \frac { 67} { 6} \right \rceil = \left \lceil 11.1667 \right \rceil = 12\]

 

 

3. Determine the Lower Class Limits:

Starting from the minimum value and adding the class width sequentially:

 

\[\begin{align*} \text { First class lower limit} &= 12 \\ \text { Second class lower limit} &= 12 + 12 = 24 \\ \text { Third class lower limit} &= 24 + 12 = 36 \\ \text { Fourth class lower limit} &= 36 + 12 = 48 \\ \text { Fifth class lower limit} &= 48 + 12 = 60 \\ \text { Sixth class lower limit} &= 60 + 12 = 72 \\ \end{align*} \]

 

 

4. Determine the Upper Class Limits:

The upper class limit is just below the next lower class limit:

 

\[\begin{align*} \text { First class upper limit} &= 23 \\ \text { Second class upper limit} &= 35 \\ \text { Third class upper limit} &= 47 \\ \text { Fourth class upper limit} &= 59 \\ \text { Fifth class upper limit} &= 71 \\ \text { Sixth class upper limit} &= 83 \\ \end{align*} \]

 

Therefore:

- The class width is 12.

- The correct lower class limits are: C. 12, 24, 36, 48, 60, 72

- The correct upper class limits are: D. 24, 36, 48, 60, 72, 83

 

Part 2

 

Given:

- Minimum = 8

- Maximum = 72

- Number of classes = 6

 

Step-by-Step Solution:

1. Calculate the Range:

 

\[\text { Range} = \text { Maximum} - \text { Minimum} = 72 - 8 = 64\]

 

 

2. Calculate the Class Width:

 

\[\text { Class Width} = \frac { \text { Range} } { \text { Number of Classes} } \]

 

Since we want the class width as a whole number, we round up:

 

\[\text { Class Width} = \left \lceil \frac { 64} { 6} \right \rceil = \left \lceil 10.6667 \right \rceil = 11\]

 

 

3. Determine the Lower Class Limits:

Starting from the minimum value and adding the class width sequentially:

 

\[\begin{align*} \text { First class lower limit} &= 8 \\ \text { Second class lower limit} &= 8 + 11 = 19 \\ \text { Third class lower limit} &= 19 + 11 = 30 \\ \text { Fourth class lower limit} &= 30 + 11 = 41 \\ \text { Fifth class lower limit} &= 41 + 11 = 52 \\ \text { Sixth class lower limit} &= 52 + 11 = 63 \\ \end{align*} \]

 

 

4. Determine the Upper Class Limits:

The upper class limit is just below the next lower class limit:

 

\[\begin{align*} \text { First class upper limit} &= 18 \\ \text { Second class upper limit} &= 29 \\ \text { Third class upper limit} &= 40 \\ \text { Fourth class upper limit} &= 51 \\ \text { Fifth class upper limit} &= 62 \\ \text { Sixth class upper limit} &= 73 \\ \end{align*} \]

 

 

Therefore:

- The class width is 11.

- The correct lower class limits are: D. 8, 19, 30, 41, 52, 63

- The correct upper class limits are: B. 18, 29, 40, 51, 62, 73

 

Part 3

 

Given:

- Minimum = 15

- Maximum = 95

- Number of classes = 8

 

Step-by-Step Solution:

 

1. Calculate the Range:

 

\[\text { Range} = \text { Maximum} - \text { Minimum} = 95 - 15 = 80\]

 

 

2. Calculate the Class Width:

\[\text { Class Width} = \frac { \text { Range} } { \text { Number of Classes} } \]

Since we want the class width as a whole number, we round up:

\[\text { Class Width} = \left \lceil \frac { 80} { 8} \right \rceil = \left \lceil 10 \right \rceil = 10\]

 

3. Determine the Lower Class Limits:

Starting from the minimum value and adding the class width sequentially:

\[\begin{align*} \text { First class lower limit} &= 15 \\ \text { Second class lower limit} &= 15 + 10 = 25 \\ \text { Third class lower limit} &= 25 + 10 = 35 \\ \text { Fourth class lower limit} &= 35 + 10 = 45 \\ \text { Fifth class lower limit} &= 45 + 10 = 55 \\ \text { Sixth class lower limit} &= 55 + 10 = 65 \\ \text { Seventh class lower limit} &= 65 + 10 = 75 \\ \text { Eighth class lower limit} &= 75 + 10 = 85 \\ \end{align*} \]

 

4. Determine the Upper Class Limits:

The upper class limit is just below the next lower class limit:

 

\[\begin{align*} \text { First class upper limit} &= 24 \\ \text { Second class upper limit} &= 34 \\ \text { Third class upper limit} &= 44 \\ \text { Fourth class upper limit} &= 54 \\ \text { Fifth class upper limit} &= 64 \\ \text { Sixth class upper limit} &= 74 \\ \text { Seventh class upper limit} &= 84 \\ \text { Eighth class upper limit} &= 94 \\ \end{align*} \]

 

 

Therefore:

- The class width is 10.

- The correct lower class limits are: B. 15, 25, 35, 45, 55, 65, 75, 85

- The correct upper class limits are: B. 24, 34, 44, 54, 64, 74, 84, 94

 

 

Additional Knowledge

Class Width Calculation:

- The class width determines the interval size for each class in a frequency distribution. It is crucial for creating histograms and other visual data representations.

 

Choosing Class Limits:

- Lower class limits start at the minimum value.

- Upper class limits are typically one less than the next lower class limit in a whole number system, ensuring there is no overlap.

 

Importance of Classes:

- Proper class intervals ensure that data is evenly distributed across classes, making the data easier to analyze and interpret.

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