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Mcdonald Fernandez
11/28/2020 · Senior High School
i) \(P= \frac { 4} { 4+ 7+ 8} = \frac { 4} { 19} \)
ii) \(P= \frac { 8} { 4+ 7+ 8} = \frac { 8} { 19} \)
iii) \(P= \frac { 4+ 7} { 4+ 7+ 8} = \frac { 11} { 19} \)
iv) \(P= 1- \frac { 8} { 4+ 7+ 8} = \frac { 11} { 19} \)
A={drawing a red ball}
B={drawing a blue ball}
\(A\cap B= \emptyset \)
So, they are mutually exclusive
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